简介

LSE 经济学挑战LSESU Economics Society Essay Competition

伦敦政治经济学院 (LSE) 作为全球经济学教育与研究的顶尖殿堂，其经济学专业常年稳居世界前列，其中经济学与计量经济学专业位列 QS 英国排名第一。依托 LSE 优质经济学学术资源，LSE 经济学挑战由 LSE 经济学教授亲自命题审核，以 “衔接高中与 LSE 本科经济学教育”为核心定位。挑战内容不仅涵盖宏观经济学、微观经济学的基础理论与定性分析能力，更创新性地融合了理论与应用数学模块，突出数学与计算能力在经济学中的核心地位，旨在培养能够利用数学工具来解决经济问题的复合型人才，推动学生顺应经济学日益数理化的全球趋势，走向经济学前沿。

2025-2026年首届举办就已覆盖全球20+国家及地区，构建起国际化的经济学学术交流平台。

顾问教授

Dr. Judith Shapiro

Supporting Professor

现任教于伦敦政治经济学院（LSE）经济学系。她曾担任日内瓦联合国欧洲经济委员会转型经济科科长，和莫斯科研 究生新经济学院教授、学术协调员和研究中心联合主席，专注于培养下一代经济学家。

LSESU 经济学挑战

LSE 经济学与计量经济学

排名英国第1

LSE 经济学挑战融合国际高中课程与 LSE 本科经济学核心内容

全球挑战
面向全球高中生的高水平学术挑战
学术支持
LSE 经济学学会提供专属备战学术材料
教授命题
由 LSE 经济学教授亲自命题与学术审核
官方主办
伦敦政治经济学院 (LSE) 最大、最具影响力的学会——经济学学会官方主办，是 LSE 经济系唯一官方支持的学术学会 官网：https://lsesueconsoc.org/

经济 × 数学

伦敦政治经济学院 (LSE) 作为全球经济学教育与研究的顶尖殿堂，其经济学专业常年稳居世界前列。其中经济学与计量经济学专业位列 QS 英国排名第一。并在 2026 年申请季推出全新专业——经济与数据科学专业。为何 LSE 如此重视经济和数学的结合？因为前者奠定了理论基石，后者提供了逻辑工具和实证方法，使经济学从一门思辨性的社会科学转变为一门更具科学性、精确性和预测性的学科。在大数据时代，不论是互联网、金融科技、投资银行、公共政策等领域，都高度依赖既懂经济学又具备强大数学分析能力的人才。

本次 LSE 经济学会发起的经济学挑战项目，充分体现了其在经济学人才培养方面的前瞻性洞察。依托 LSE 优质经济学学术资源，LSE 经济学挑战由 LSE 经济学教授亲自命题审核，以 “衔接高中与 LSE 本科经济学教育”为核心定位。挑战内容不仅涵盖宏观经济学、微观经济学的基础理论与定性分析能力，更创新性地融合了TMUA考核体系的理论数学模块与应用数学模块，突出数学与计算能力在经济学中的核心地位，旨在培养能够利用多元数学工具来解决经济问题的复合型人才，推动学生顺应经济学日益数理化的全球趋势，走向经济学前沿。

学术模块

样题

本挑战设计为50%高中标化课程标准，50% LSE经济本科大一标准的题目。咬合衔接升学知识点，帮助申请英国名校方向的经济菁英锚定正确方向，定向拉伸知识技能。

本挑战题目由LSE经济学教授亲自命题与学术审核

1.

If the consumer price index was 75 in the base year and 130 in the following year, then the inflation rate was
a.57%
b.58%
c.73%
d.42%

Explanation:

Inflation rate = percentage change of CPI = ((130/75)-1)x100%

2.

Assume the MPC = 0.75 and considering only the multiplier effect, if government taxation increases by $60 billion, then national income will
a.Decrease 45 billion.
b.Decrease 240 billion.
c.Increase 240 billion.
d.Decrease 180 billion.

Explanation:

multiplier = 1/(1-MPC) = 1/ (1-0.75) =4.

Potential change in national change income = multiplier x tax change x MPC = 4x60x0.75=180

3.

Ms. Jane resigned from her job with a $60,000 annual salary to open a coffee shop in her apartment. Her coffee shop’s annual revenue is $80,000, and her costs for coffee beans, facility maintenance, water, and electricity amount to $30,000 per year. Should Ms. Jane be satisfied with her coffee shop’s annual profit?
a.Yes, because her accounting profit is $50,000
b.Yes, because her economic profit is $50,000
c.No, because her economic loss is $20,000
d.No, because her economic loss is $10,000

Explanation:

Economic profit = Accounting profit – Implicit cost = $80,000 - $30,000 - $60,000 = -$10,000.

4.

Dawn, Inc. produces and sells notebook in a perfectly competitive market at the price of $3 per unit and hires all the workers it needs at the wage rate of $23. Assume worker is the only variable input, and the firm’s production schedule is provided in table.
Number of workersQuantity of Notebook
00
110
221
328
433
Determine the profit-maximizing number of workers the firm should hire.
a.1
b.2
c.3
d.4

Explanation:

The firm maximizes profit where the value of the additional worker’s contribution (Marginal revenue) is just equal to or greater than the wage(Marginal cost). Hiring a third worker would add only $21 of revenue while costing $23, leading to a loss. Thus, the profit-maximizing number of workers is 2.

5.

Researcher Keynes is doing a field experiment.He discovers a random variable X that takes: ● X =2 with probability 0.4 ● X =10 with probability 0.6 What is E[X]and Var[X]?
A.15.36,6.80
B.5.20,15.36
C.5.20,6.80
D.6.80,15.36 √

Explanation:

The expected value of a discrete random variable is calculated as the sum of each possible value multiplied by its probability.For random variable X,which takes the value 2 with probability 0.4 and 10 with probability 0.6,E [X]=(20.4)+(100 .6)=0.8 +6=6.80.The variance of a discrete random variable is calculated as E[X²]-(E[X])². First, calculate E[X²]:E[X²]=(2²0.4)+(10²0.6)=(40 .4)+(1000 .6)=1.6 +60 =61.6.Then, Var[X]=61.6 -(6 .80)²=61.6 -46.24 =15.36.

6.

A researcher has a null hypothesis that study hours have no effect on exam scores.Using data, the researcher obtains an estimate of the effect of 2.5 with a standard error of 0.5.What is the value of the t-statistic in this context?
A.0.20
B.1.25
C.2.50
D.5.00 √

Explanation:

The t-statistic measures the ratio of the magnitude of an estimate to its standard error.It is calculated as the estimate divided by the standard error.Substituting these values into the t-statistic formula gives 2.5 /0.5 =5.00.

7.

How many solutions are there to (1 + 3 cos 3 θ )2 = 4 in the interval 0° ≤ θ ≤ 180° ?

A.3

B.4

C.5 √

D.6

Explanation:

We have (1 + 3cos3θ)2 = 4 if and only if 1 + 3cos3θ = ±2. We consider each possibility separately.
We have1 +3cos3θ = 2
if and only if 3cos3θ = 1
if and only if cos3θ = 1/3.
Since 0° ≤ θ ≤ 180° , we have 0° ≤ 3θ ≤ 540° , and there are 3 values of 3θ which have cos3θ = 1/3 in this interval. (One is
between 0° and 90° , one is between 270° and 360° , and one is between 360° and 450° , by considering the graph of y =
cosx.)
Now considering the other possibility, we have1 +3cos3θ = − 2
if and only if 3cos3θ = − 3
if and only if cos3θ = − 1.
Again, 0° ≤ 3θ ≤ 540° , but this time there are only 2 values of 3θ which satisfy the equation: 3θ = 180 and 3θ = 540° .
Neither of these values of 3θ overlap with the values of 3θ found earlier, so in total there are 3 +2 = 5 values of 3θ in the
interval 0° ≤ 3θ ≤ 540° , and hence 5 solutions to the original
equation in the given interval. The correct answer is option C.

8.

Let x be a real number.
Which one of the following statements is a sufficient condition for exactly three of the other four statements?

A. x ≥ 0

B. x = 1

C. x = 0 or x = 1 √

D. x ≥ 0 or x ≤ 1

E. x ≥ 0 and x ≤ 1

Explanation:

We work through them sequentially:
A If x ≥ 0, then B may be false, C may be false, D may be false and E may be false
B If x=1, then A is true, C is true, D is true and E is true
C If x=0 or x=1, then A is true, B may be false, D is true and E is true
D If x ≥ 0 or x ≤ 1, then A may be false (for example if x = − 1), B may be false, C may be false and E may be
false
E If x ≥ 0 and x ≤ 1, then A is true, B may be false, C may be false and D is true
The correct option is therefore C, which is sufficient for exactly three of the other four statements.

挑战规则

  • 适合年级：适合年级:9-12年级
  • 形式：50道选择题（线上/线下纸质）
  • 时长：90分钟
  • 语言：英文
  • 参与形式：个人挑战
  • 挑战日期：2027年1月